Let for $j=0, \ldots, n, a_{j}=a_{0}+j d$, where $a_{0}, d$ are fixed real numbers. Put
$$
A=\left(\begin{array}{ccccc}
a_{0} & a_{1} & a_{2} & \ldots & a_{n} \\
a_{1} & a_{0} & a_{1} & \ldots & a_{n-1} \\
a_{2} & a_{1} & a_{0} & \ldots & a_{n-2} \\
\ldots & \ldots & \ldots \ldots \ldots & \ldots & \ldots \\
a_{n} & a_{n-1} & a_{n-2} & \ldots & a_{0}
\end{array}\right)
$$
Calculate $\operatorname{det}(A)$, where $\operatorname{det}(A)$ denotes the determinant of $A$. Please provide the value of $\operatorname{det}(A)$ when $a_0 = 0$, $a_n = 1,n=4$, and $d = 0$

Let's think step by step and output the final answer within \boxed{}.
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