In triangle $ABC,$ $D$ is on $\overline{AB}$ such that $AD:DB = 3:2,$ and $E$ is on $\overline{BC}$ such that $BE:EC = 3:2.$  If lines $DE$ and $AC$ intersect at $F,$ then find $\frac{DE}{EF}.$The answer is in the form rac{m}{n}, where gcd(m, n) = 1. Please provide the value of m + n.

Let's think step by step and output the final answer within \boxed{}.
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