$ABCD$ forms a rhombus. $E$ is the intersection of $AC$ and $BD$. $F$ lies on $AD$ such that $EF$ is perpendicular to $FD$. Given $EF = 2$ and $FD = 1$. Find the area of the rhombus $ABCD$.

Let's think step by step and output the final answer within \boxed{}.
user