In $\triangle ABC$, $\angle ABC=45^\circ$. Point $D$ is on $\overline{BC}$ so that $2\cdot BD=CD$ and $\angle DAB=15^\circ$. If the answer is $x^\circ$, find the value of $x$ for $\angle ACB$.

Let's think step by step and output the final answer within \boxed{}.
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