Let \(H\) be the intersection of altitudes in triangle \(ABC\). If \(\angle B = \angle C = \alpha\) and \(O\) is the center of the circle passing through \(A\), \(H\), and \(C\), then find \(\angle HOC\) in terms of \(\alpha\) and express your answer in degrees. The original answer is in the form \(k^\circ - m\alpha\), please give the value of \(k + m\).

Let's think step by step and output the final answer within \boxed{}.
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