A square $ABCD$ with sides of length 1 is divided into two congruent trapezoids and a pentagon, which have equal areas, by joining the center of the square with points $E, F, G$ where $E$ is the midpoint of $BC$, $F$ and $G$ are on $AB$ and $CD$, respectively. They are positioned such that $AF < FB$, $DG < GC$, and $F$ is directly opposite $G$. If $FB = x$, the length of the longer parallel side of each trapezoid, find the value of $x$. The original answer is in the form of \frac{k}{m}, please give the value of k + m.

Let's think step by step and output the final answer within \boxed{}.
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