Let $XYZ$ be a right triangle with an area of $1 \text{ m}^2$. Consider the triangle $X'Y'Z'$ such that:
- $X'$ is the symmetric of $X$ with respect to side $YZ$.
- $Y'$ is the symmetric of $Y$ with respect to side $XZ$.
- $Z'$ is the symmetric of $Z$ with respect to side $XY$.

Calculate the area of the triangle $X'Y'Z'$.

Let's think step by step and output the final answer within \boxed{}.
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