Find the value of $6+\frac{1}{2+\frac{1}{6+\frac{1}{2+\frac{1}{6+\cdots}}}}$. Your answer will be of the form $a+b\sqrt{c}$ where no factor of $c$ (other than $1$) is a square. Find $a+b+c$.

Let's think step by step and output the final answer within \boxed{}.
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